Question

For a real number aa, let I(a)=∫−11(3x2−ax+1) dxI(a) = \int_{-1}^{1} (3x^2 - ax + 1)\,dx. Which of the following statements is/are true?

Choose every correct option
Official answer and solution
Official answer
A and C
From
Official GATE 2026 answer key

Solution

Evaluate the definite integral over the symmetric interval [−1,1][-1, 1] using even and odd function properties.

Splitting the integrand into even and odd terms over [−1,1][-1, 1]:

I(a)=∫−11(3x2+1) dx−a∫−11x dxI(a) = \int_{-1}^{1} (3x^2 + 1)\,dx - a \int_{-1}^{1} x\,dx

Since xx is an odd function, ∫−11x dx=0\int_{-1}^{1} x\,dx = 0 for every real aa. For the even part:

I(a)=2∫01(3x2+1) dx=2[x3+x]01=2(1+1)=4I(a) = 2 \int_{0}^{1} (3x^2 + 1)\,dx = 2 \left[x^3 + x\right]_0^1 = 2(1 + 1) = 4

Since I(a)=4>0I(a) = 4 > 0 for all a∈Ra \in \mathbb{R}, I(a)I(a) is independent of aa (A) and is a positive real number for all aa (C).

Final answer

Options (A), (C)

The answer is the one in the official GATE answer key. The solution is this site's own explanation.

Source

Paper
GATE 2026 Computer Science and Information Technology - Session 2 (CS2)
Question
27 of 65
Section
Computer Science and Information Technology

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