Question

Let F\mathcal{F} be the set of all functions from {1,…,n}\{1, \dots, n\} to {0,1}\{0, 1\}. Define the binary relation ≼\preccurlyeq on F\mathcal{F} as follows:

∀f,g∈F,  f≼g\forall f, g \in \mathcal{F}, \; f \preccurlyeq g if and only if ∀x∈{1,…,n},  f(x)≤g(x)\forall x \in \{1, \dots, n\}, \; f(x) \le g(x), where 0≤10 \le 1.

Which of the following statement(s) is/are TRUE?

Choose every correct option
Official answer and solution
Official answer
B and C
From
Official GATE 2025 answer key

Solution

Check reflexivity, antisymmetry, transitivity, and the existence of pointwise meet (min⁡\min) and join (max⁡\max) on F={0,1}n\mathcal{F} = \{0, 1\}^n.

The relation ≼\preccurlyeq is the pointwise product order on {0,1}n\{0, 1\}^n (isomorphic to (P({1,…,n}),⊆)(\mathcal{P}(\{1, \dots, n\}), \subseteq)):

  • Reflexive: f(x)≤f(x)f(x) \le f(x) for all xx, so f≼ff \preccurlyeq f.
  • Antisymmetric: If f(x)≤g(x)f(x) \le g(x) and g(x)≤f(x)g(x) \le f(x) for all xx, then f=gf = g. (Hence ≼\preccurlyeq is not symmetric, ruling out A and D).
  • Transitive: If f≼gf \preccurlyeq g and g≼hg \preccurlyeq h, then f(x)≤g(x)≤h(x)f(x) \le g(x) \le h(x) for all xx, so f≼hf \preccurlyeq h.
    Thus (F,≼)(\mathcal{F}, \preccurlyeq) is a partial order (B).
  • Moreover, every pair f,g∈Ff, g \in \mathcal{F} has a greatest lower bound glb(f,g)(x)=min⁡(f(x),g(x))\text{glb}(f, g)(x) = \min(f(x), g(x)) and a least upper bound lub(f,g)(x)=max⁡(f(x),g(x))\text{lub}(f, g)(x) = \max(f(x), g(x)) in F\mathcal{F}, so (F,≼)(\mathcal{F}, \preccurlyeq) is a lattice (C).
Final answer

Options (B), (C)

The answer is the one in the official GATE answer key. The solution is this site's own explanation.

Source

Paper
GATE 2025 Computer Science and Information Technology - Session 2 (CS2)
Question
42 of 65
Section
Computer Science and Information Technology

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