Question

A person sold two different items at the same price. He made 10% profit in one item, and 10% loss in the other item. In selling these two items, the person made a total of

Choose one option
Official answer and solution
Official answer
C
From
Official GATE 2024 answer key

Solution

Express the cost prices of both items in terms of the common selling price SS and compare total selling price with total cost price.

Let the selling price of each item be S=99S = 99.

  • For the first item (10% profit): C1=991.1=90C_1 = \frac{99}{1.1} = 90.
  • For the second item (10% loss): C2=990.9=110C_2 = \frac{99}{0.9} = 110.
  • Total cost price =C1+C2=90+110=200= C_1 + C_2 = 90 + 110 = 200.
  • Total selling price =2S=99+99=198= 2S = 99 + 99 = 198.

Since 198<200198 < 200, there is a net loss of 200−198200×100%=1%\frac{200 - 198}{200} \times 100\% = 1\% loss. (In general, selling two items at the same price with p%p\% gain on one and p%p\% loss on the other always results in a p2100%\frac{p^2}{100}\% loss.)

Final answer

Option (C)

Common trap

Adding +10%+10\% and −10%-10\% directly without noting that the percentages are taken on different cost prices.

The answer is the one in the official GATE answer key. The solution is this site's own explanation.

Source

Paper
GATE 2024 Computer Science and Information Technology - Set 2 (CS2)
Question
7 of 65
Section
General Aptitude

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