Question

The chromatic number of a graph is the minimum number of colours used in a proper colouring of the graph. Let GG be any graph with nn vertices and chromatic number kk. Which of the following statements is/are always TRUE?

Choose every correct option
Official answer and solution
Official answer
B and C
From
Official GATE 2024 answer key

Solution

Analyze the kk color classes of an optimal proper kk-coloring of GG.

Consider an optimal proper kk-colouring of GG, which partitions the nn vertices into kk colour classes V1,V2,…,VkV_1, V_2, \dots, V_k.

  • (A) is FALSE: A graph with chromatic number kk need not contain KkK_k as a subgraph (for example, the odd cycle C5C_5 has chromatic number k=3k = 3 but contains no K3K_3).
  • (B) is TRUE: Each colour class ViV_i is an independent set, and ∑i=1k∣Vi∣=n\sum_{i=1}^k |V_i| = n. By the Pigeonhole Principle, max⁡i∣Vi∣≥n/k\max_i |V_i| \ge n/k, so GG contains an independent set of size at least n/kn/k.
  • (C) is TRUE: Between every pair of distinct colour classes (Vi,Vj)(V_i, V_j) with 1≤i<j≤k1 \le i < j \le k, there must be at least one edge in GG (otherwise ViV_i and VjV_j could be merged into a single colour class, giving a valid (k−1)(k-1)-colouring of GG). Since there are (k2)=k(k−1)2\binom{k}{2} = \frac{k(k-1)}{2} pairs of colour classes, GG must contain at least k(k−1)/2k(k-1)/2 edges.
  • (D) is FALSE: A graph with chromatic number kk only requires maximum degree Δ(G)≥k−1\Delta(G) \ge k - 1 (for example, KkK_k has chromatic number kk, and every vertex has degree k−1<kk - 1 < k).
Final answer

Options (B), (C)

Common trap

Assuming a graph with chromatic number kk must have a vertex of degree kk (forgetting that KkK_k has maximum degree k−1k-1).

The answer is the one in the official GATE answer key. The solution is this site's own explanation.

Source

Paper
GATE 2024 Computer Science and Information Technology - Set 1 (CS1)
Question
51 of 65
Section
Computer Science and Information Technology

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