Question

Consider two functions of time (tt),

f(t)=0.01t2f(t) = 0.01 t^2
g(t)=4tg(t) = 4t

where 0<t<∞0 < t < \infty.

Now consider the following two statements:
(i) For some t>0t > 0, g(t)>f(t)g(t) > f(t).
(ii) There exists a TT, such that f(t)>g(t)f(t) > g(t) for all t>Tt > T.

Which one of the following options is TRUE?

Choose one option
Official answer and solution
Official answer
C
From
Official GATE 2023 answer key

Solution

Analyze the inequality f(t)=0.01t2f(t) = 0.01 t^2 versus g(t)=4tg(t) = 4t for t>0t > 0.

Consider the two functions for t>0t > 0:

  1. For statement (i): g(t)>f(t)  ⟺  4t>0.01t2g(t) > f(t) \iff 4t > 0.01 t^2. Since t>0t > 0, dividing by tt gives 4>0.01t  ⟺  t<4004 > 0.01 t \iff t < 400. For any t∈(0,400)t \in (0, 400), such as t=10t = 10, g(10)=40>f(10)=1g(10) = 40 > f(10) = 1. Thus, statement (i) is true.

  2. For statement (ii): f(t)>g(t)  ⟺  0.01t2>4t  ⟺  t>400f(t) > g(t) \iff 0.01 t^2 > 4t \iff t > 400. Choosing T=400T = 400, for all t>400t > 400, f(t)>g(t)f(t) > g(t). Thus, statement (ii) is true.

Both statements (i) and (ii) are correct.

Final answer

Option (C)

Common trap

Failing to recognize that quadratic growth eventually dominates linear growth for sufficiently large tt.

The answer is the one in the official GATE answer key. The solution is this site's own explanation.

Source

Paper
GATE 2023 Computer Science and Information Technology (CS)
Question
7 of 65
Section
General Aptitude

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