Question

Let XX be a set and 2X2^X denote the powerset of XX. Define a binary operation Δ\Delta on 2X2^X as follows:

AΔB=(A−B)∪(B−A).A \Delta B = (A - B) \cup (B - A).

Let H=(2X,Δ)H = (2^X, \Delta). Which of the following statements about HH is/are correct?

Choose every correct option
Official answer and solution
Official answer
A and D
From
Official GATE 2023 answer key

Solution

Verify group axioms for the symmetric difference operation Δ\Delta on powerset 2X2^X.

Let H=(2X,Δ)H = (2^X, \Delta) where AΔB=(A−B)∪(B−A)A \Delta B = (A - B) \cup (B - A):

  1. Closure: For any A,B⊆XA, B \subseteq X, AΔB⊆XA \Delta B \subseteq X, so AΔB∈2XA \Delta B \in 2^X.
  2. Associativity: Symmetric difference is associative: (AΔB)ΔC=AΔ(BΔC)(A \Delta B) \Delta C = A \Delta (B \Delta C) holds for all subsets.
  3. Identity Element: The empty set ∅\emptyset serves as the identity element because AΔ∅=(A−∅)∪(∅−A)=AA \Delta \emptyset = (A - \emptyset) \cup (\emptyset - A) = A.
  4. Inverses: For every A∈2XA \in 2^X, AΔA=(A−A)∪(A−A)=∅A \Delta A = (A - A) \cup (A - A) = \emptyset. Thus, the inverse of AA is AA itself (every element is self-inverse).

Since closure, associativity, identity, and inverses all exist, HH is a group (an abelian group of exponent 2). Therefore, statements (A) and (D) are correct.

Final answer

Options (A, D)

Common trap

Thinking the inverse is the set complement X−AX - A, whereas AΔ(X−A)=X≠∅A \Delta (X - A) = X \neq \emptyset.

The answer is the one in the official GATE answer key. The solution is this site's own explanation.

Source

Paper
GATE 2023 Computer Science and Information Technology (CS)
Question
51 of 65
Section
Computer Science and Information Technology

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