Question

Let

f(x)=x3+15x2−33x−36f(x) = x^3 + 15x^2 - 33x - 36

be a real-valued function.

Which of the following statements is/are TRUE?

Choose every correct option
Official answer and solution
Official answer
B and D
From
Official GATE 2023 answer key

Solution

Find critical points using the first derivative and test their nature using the second derivative.

Given f(x)=x3+15x2−33x−36f(x) = x^3 + 15x^2 - 33x - 36:

  1. First derivative:

    f′(x)=3x2+30x−33=3(x2+10x−11)=3(x+11)(x−1)f'(x) = 3x^2 + 30x - 33 = 3(x^2 + 10x - 11) = 3(x + 11)(x - 1)

    Setting f′(x)=0f'(x) = 0 yields critical points at x=−11x = -11 and x=1x = 1.

  2. Second derivative:

    f′′(x)=6x+30f''(x) = 6x + 30
    • At x=−11x = -11: f′′(−11)=6(−11)+30=−36<0f''(-11) = 6(-11) + 30 = -36 < 0, which signifies a local maximum at x=−11x = -11.
    • At x=1x = 1: f′′(1)=6(1)+30=36>0f''(1) = 6(1) + 30 = 36 > 0, which signifies a local minimum at x=1x = 1.

Therefore, f(x)f(x) has a local maximum (statement B is TRUE) and f(x)f(x) has a local minimum (statement D is TRUE).

Final answer

Options (B, D)

Common trap

Selecting only one extremum or confusing the signs of f′′(x)f''(x) (f′′<0f'' < 0 implies local maximum).

The answer is the one in the official GATE answer key. The solution is this site's own explanation.

Source

Paper
GATE 2023 Computer Science and Information Technology (CS)
Question
28 of 65
Section
Computer Science and Information Technology

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