Question

Suppose that PP is a 4×54 \times 5 matrix such that every solution of the equation Px=0Px = 0 is a scalar multiple of [2  5  4  3  1]T[2\; 5\; 4\; 3\; 1]^T. The rank of PP is ______.

Official answer and solution
Official answer
4
From
Official GATE 2021 answer key

Solution

Use the Rank-Nullity Theorem by relating the dimension of the solution space of the homogeneous linear system to the matrix rank.

The matrix PP has dimensions 4×54 \times 5, so the number of columns (the dimension of the domain) is n=5n = 5.

The set of all solutions to the homogeneous equation Px=0Px = 0 is the null space (kernel) of PP, denoted Null(P)\text{Null}(P).

We are given that every solution of Px=0Px = 0 is a scalar multiple of the single non-zero vector [2  5  4  3  1]T[2\; 5\; 4\; 3\; 1]^T. This means the null space is spanned by one non-zero vector, so its dimension (nullity) is:

nullity(P)=dim⁡(Null(P))=1\text{nullity}(P) = \dim(\text{Null}(P)) = 1

By the Rank-Nullity Theorem:

rank(P)+nullity(P)=n\text{rank}(P) + \text{nullity}(P) = n
rank(P)+1=5  ⟹  rank(P)=4\text{rank}(P) + 1 = 5 \implies \text{rank}(P) = 4
Final answer

4

The answer is the one in the official GATE answer key. The solution is this site's own explanation.

Source

Paper
GATE 2021 Computer Science and Information Technology - Session 2 (CS2)
Question
34 of 65, printed as CS Q.24
Section
Computer Science and Information Technology

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