Question

Consider the two statements.

S1:There exist random variables X and Y such that (E[(X−E[X])(Y−E[Y]))2>Var[X]Var[Y]S_1: \text{There exist random variables } X \text{ and } Y \text{ such that } \left(E[(X - E[X])(Y - E[Y])\right)^2 > \text{Var}[X]\text{Var}[Y]
S2:For all random variables X and Y,Cov[X,Y]=E[∣X−E[X]∣∣Y−E[Y]∣]S_2: \text{For all random variables } X \text{ and } Y, \quad \text{Cov}[X, Y] = E[|X - E[X]||Y - E[Y]|]

Which one of the following choices is correct?

Choose one option
Official answer and solution
Official answer
D
From
Official GATE 2021 answer key

Solution

Evaluate each statement against the Cauchy-Schwarz inequality and the definition of covariance.

Analyze statement S1S_1: By definition, Cov[X,Y]=E[(X−E[X])(Y−E[Y])]\text{Cov}[X, Y] = E[(X - E[X])(Y - E[Y])]. The Pearson correlation coefficient ρ\rho is defined as:

ρ=Cov[X,Y]Var[X]Var[Y]\rho = \frac{\text{Cov}[X, Y]}{\sqrt{\text{Var}[X]\text{Var}[Y]}}

By the Cauchy-Schwarz inequality, ∣ρ∣≤1|\rho| \le 1 for all random variables with non-zero variances, which implies (Cov[X,Y])2≤Var[X]Var[Y](\text{Cov}[X, Y])^2 \le \text{Var}[X]\text{Var}[Y]. The strict inequality (Cov[X,Y])2>Var[X]Var[Y](\text{Cov}[X, Y])^2 > \text{Var}[X]\text{Var}[Y] is mathematically impossible. Hence, S1S_1 is false.

Analyze statement S2S_2: The definition of covariance is Cov[X,Y]=E[(X−E[X])(Y−E[Y])]\text{Cov}[X, Y] = E[(X - E[X])(Y - E[Y])], without absolute values. The absolute-value expression E[∣X−E[X]∣∣Y−E[Y]∣]E[|X - E[X]||Y - E[Y]|] is always non-negative, whereas covariance can be negative (when XX and YY are negatively correlated). Hence, S2S_2 is false.

Because both S1S_1 and S2S_2 are false, option D is correct.

Final answer

D

The answer is the one in the official GATE answer key. The solution is this site's own explanation.

Source

Paper
GATE 2021 Computer Science and Information Technology (CS, Set-1)
Question
45 of 65, printed as CS Q.35
Section
Computer Science and Information Technology

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