Question

Graph GG is obtained by adding vertex ss to K3,4K_{3,4} and making ss adjacent to every vertex of K3,4K_{3,4}. The minimum number of colours required to edge-colour GG is _______.

Official answer and solution
Official answer
7
From
Official GATE 2020 answer key

Solution

Apply Vizing's theorem and edge-coloring properties to graph G = K_{3,4} + s.

Graph structure of GG:

  • Let the complete bipartite graph K3,4K_{3,4} have bipartition (A,B)(A, B) with ∣A∣=3|A| = 3 and ∣B∣=4|B| = 4.
  • Vertex ss is added and connected to every vertex of K3,4K_{3,4}.
  • Total vertices in GG: ∣V(G)∣=3+4+1=8|V(G)| = 3 + 4 + 1 = 8 vertices.

Degrees of vertices in GG:

  • Vertex ss is adjacent to all 7 vertices of K3,4  ⟹  deg⁡(s)=7K_{3,4} \implies \deg(s) = 7.
  • Each vertex u∈Au \in A is adjacent to 4 vertices in BB plus vertex s  ⟹  deg⁡(u)=4+1=5s \implies \deg(u) = 4 + 1 = 5.
  • Each vertex v∈Bv \in B is adjacent to 3 vertices in AA plus vertex s  ⟹  deg⁡(v)=3+1=4s \implies \deg(v) = 3 + 1 = 4.
  • The maximum degree of GG is Δ(G)=deg⁡(s)=7\Delta(G) = \deg(s) = 7.

Chromatic index bounds:

  • By definition of proper edge-coloring, all edges incident to a common vertex must receive distinct colors. Thus, the chromatic index χ′(G)≥Δ(G)=7\chi'(G) \ge \Delta(G) = 7.
  • By Vizing's Theorem, χ′(G)\chi'(G) is either Δ(G)=7\Delta(G) = 7 (Class 1) or Δ(G)+1=8\Delta(G) + 1 = 8 (Class 2).
  • Since GG has 8 vertices, the maximum size of any matching is 8/2=48 / 2 = 4 edges. Total edges ∣E∣=(3×4)+7=19|E| = (3 \times 4) + 7 = 19. 7 matchings can accommodate up to 7×4=28≥197 \times 4 = 28 \ge 19 edges, and a valid 7-edge-coloring can be explicitly constructed (Class 1).
  • Therefore, the minimum number of colours required is 7.
Final answer

7

The answer is the one in the official GATE answer key. The solution is this site's own explanation.

Source

Paper
GATE 2020 Computer Science and Information Technology (CS)
Question
62 of 65, printed as CS Q.52
Section
Computer Science and Information Technology

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