Question

Let AA and BB be two n×nn \times n matrices over real numbers. Let rank(M)\text{rank}(M) and det⁡(M)\det(M) denote the rank and determinant of a matrix MM, respectively. Consider the following statements.

I. rank(AB)=rank(A)⋅rank(B)\text{rank}(AB) = \text{rank}(A) \cdot \text{rank}(B)
II. det⁡(AB)=det⁡(A)⋅det⁡(B)\det(AB) = \det(A) \cdot \det(B)
III. rank(A+B)≤rank(A)+rank(B)\text{rank}(A + B) \le \text{rank}(A) + \text{rank}(B)
IV. det⁡(A+B)≤det⁡(A)+det⁡(B)\det(A + B) \le \det(A) + \det(B)

Which of the above statements are TRUE?

Choose one option
Official answer and solution
Official answer
C
From
Official GATE 2020 answer key

Solution

Evaluate standard linear algebra properties for matrix rank and determinant.

Statement I: rank(AB)=rank(A)⋅rank(B)\text{rank}(AB) = \text{rank}(A) \cdot \text{rank}(B)

  • Counterexample: Let A=I2A = I_2 and B=I2B = I_2 (identity matrices of size 2×22 \times 2).
  • rank(A)=2\text{rank}(A) = 2, rank(B)=2\text{rank}(B) = 2, so rank(A)⋅rank(B)=4\text{rank}(A) \cdot \text{rank}(B) = 4.
  • But AB=I2AB = I_2 which has rank 2, not 4. Statement I is FALSE.

Statement II: det⁡(AB)=det⁡(A)⋅det⁡(B)\det(AB) = \det(A) \cdot \det(B)

  • This is a fundamental theorem of determinants for square matrices over any field. Statement II is TRUE.

Statement III: rank(A+B)≤rank(A)+rank(B)\text{rank}(A + B) \le \text{rank}(A) + \text{rank}(B)

  • The column space of A+BA + B is contained within the sum of the column spaces of AA and BB: col(A+B)⊆col(A)+col(B)\text{col}(A+B) \subseteq \text{col}(A) + \text{col}(B).
  • By dimension of subspaces: dim⁡(col(A+B))≤dim⁡(col(A))+dim⁡(col(B))\dim(\text{col}(A+B)) \le \dim(\text{col}(A)) + \dim(\text{col}(B)). Statement III is TRUE.

Statement IV: det⁡(A+B)≤det⁡(A)+det⁡(B)\det(A + B) \le \det(A) + \det(B)

  • Counterexample: Let A=I2A = I_2 and B=I2B = I_2.
  • det⁡(A)=1\det(A) = 1, det⁡(B)=1\det(B) = 1, so det⁡(A)+det⁡(B)=2\det(A) + \det(B) = 2.
  • A+B=2I2A + B = 2I_2, so det⁡(A+B)=det⁡(2I2)=22⋅1=4\det(A + B) = \det(2I_2) = 2^2 \cdot 1 = 4.
  • Since 4≰24 \not\le 2, Statement IV is FALSE.

Therefore, statements II and III only are TRUE.

Final answer

C

The answer is the one in the official GATE answer key. The solution is this site's own explanation.

Source

Paper
GATE 2020 Computer Science and Information Technology (CS)
Question
37 of 65, printed as CS Q.27
Section
Computer Science and Information Technology

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