Question

Let uu and vv be two vectors in R2\mathbb{R}^2 whose Euclidean norms satisfy ∥u∥=2∥v∥\|u\| = 2 \|v\|. What is the value of α\alpha such that w=u+αvw = u + \alpha v bisects the angle between uu and vv?

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Official answer and solution
Official answer
A
From
Official GATE 2017 answer key

Solution

Express the angle bisector of two vectors using unit vectors and solve for the scalar coefficient α\alpha.

Let uu and vv be non-zero vectors in R2\mathbb{R}^2 with angle θ\theta between them. A vector ww bisects the angle between uu and vv if it makes equal angles with uu and vv:

u⋅w∥u∥∥w∥=v⋅w∥v∥∥w∥\frac{u \cdot w}{\|u\| \|w\|} = \frac{v \cdot w}{\|v\| \|w\|}

Geometrically, the sum of unit vectors u^+v^=u∥u∥+v∥v∥\hat{u} + \hat{v} = \frac{u}{\|u\|} + \frac{v}{\|v\|} points along the angle bisector. Any positive scalar multiple of this sum is also an angle bisector vector:

w=k(u∥u∥+v∥v∥)w = k \left(\frac{u}{\|u\|} + \frac{v}{\|v\|}\right)

Choosing k=∥u∥k = \|u\| to match the coefficient 1 for uu:

w=u+∥u∥∥v∥vw = u + \frac{\|u\|}{\|v\|} v

Comparing with w=u+αvw = u + \alpha v, we have:

α=∥u∥∥v∥\alpha = \frac{\|u\|}{\|v\|}

We are given that ∥u∥=2∥v∥\|u\| = 2 \|v\|, which implies:

α=2∥v∥∥v∥=2\alpha = \frac{2 \|v\|}{\|v\|} = 2

Thus, α=2\alpha = 2.

Final answer

A

The answer is the one in the official GATE answer key. The solution is this site's own explanation.

Source

Paper
GATE 2017 Computer Science and Information Technology (CS) Session 1
Question
30 of 65, printed as CS Q.30
Section
Computer Science and Information Technology

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