Question

In a quadratic function, the value of the product of the roots (α,β)(\alpha, \beta) is 4. Find the value of

αn+βnα−n+β−n\frac{\alpha^n + \beta^n}{\alpha^{-n} + \beta^{-n}}
Choose one option
Official answer and solution
Official answer
B
From
Official GATE 2016 answer key

Solution

Rewrite the denominator using positive exponents and simplify the algebraic fraction.

Let α\alpha and β\beta be the roots of the quadratic function. We are given:

αβ=4\alpha \beta = 4

We need to evaluate the expression:

E=αn+βnα−n+β−nE = \frac{\alpha^n + \beta^n}{\alpha^{-n} + \beta^{-n}}

Express the denominator using common positive powers:

α−n+β−n=1αn+1βn=βn+αnαnβn=αn+βn(αβ)n\alpha^{-n} + \beta^{-n} = \frac{1}{\alpha^n} + \frac{1}{\beta^n} = \frac{\beta^n + \alpha^n}{\alpha^n \beta^n} = \frac{\alpha^n + \beta^n}{(\alpha \beta)^n}

Substitute this back into EE:

E=αn+βnαn+βn(αβ)n=(αβ)nE = \frac{\alpha^n + \beta^n}{\frac{\alpha^n + \beta^n}{(\alpha \beta)^n}} = (\alpha \beta)^n

Substitute the given product of roots αβ=4\alpha \beta = 4:

E=4nE = 4^n

Thus, the expression evaluates to 4n4^n.

Final answer

B

Common trap

Trying to solve for individual roots α\alpha and β\beta, which cannot be uniquely determined from the product alone.

The answer is the one in the official GATE answer key. The solution is this site's own explanation.

Source

Paper
GATE 2016 Computer Science and Information Technology (CS) Session 2
Question
5 of 65, printed as GA Q.5
Section
General Aptitude

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