Question

The value of

lim⁡x→4sin⁡(x−4)x−4\lim_{x \to 4} \frac{\sin(x - 4)}{x - 4}

is _____.

Official answer and solution
Official answer
1
From
Official GATE 2016 answer key

Solution

Substitute u=x−4u = x - 4 to evaluate the standard limit lim⁡u→0sin⁡uu\lim_{u \to 0} \frac{\sin u}{u}.

We evaluate the limit:

L=lim⁡x→4sin⁡(x−4)x−4L = \lim_{x \to 4} \frac{\sin(x - 4)}{x - 4}

Let u=x−4u = x - 4. As x→4x \to 4, u→0u \to 0. Substituting uu:

L=lim⁡u→0sin⁡uuL = \lim_{u \to 0} \frac{\sin u}{u}

From fundamental calculus (or applying L'Hopital's rule on the 0/00/0 indeterminate form):

lim⁡u→0sin⁡uu=lim⁡u→0cos⁡u1=cos⁡(0)=1\lim_{u \to 0} \frac{\sin u}{u} = \lim_{u \to 0} \frac{\cos u}{1} = \cos(0) = 1
Final answer

1

Common trap

Evaluating sin⁡(0)/0\sin(0)/0 as undefined without applying standard limits or L'Hopital's rule.

The answer is the one in the official GATE answer key. The solution is this site's own explanation.

Source

Paper
GATE 2016 Computer Science and Information Technology (CS) Session 1
Question
13 of 65, printed as CS Q.3
Section
Computer Science and Information Technology

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