GATE CS Mastery
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GATE CS 2015 Set 3 · General Aptitude

Question 1

MCQPrinted as GA Q.11 markWrong answer: −1/3Easy (estimate)

Question

If ROAD is written as URDG, then SWAN should be written as:

Choose one option
Official answer and solution
Official answer
B
From
Official GATE 2015 answer key

Solution

Identify the letter-shifting rule applied to each character of the word.

Analyze the transformation from ROAD to URDG:

  • R (position 18) →\to U (position 21): +3+3
  • O (position 15) →\to R (position 18): +3+3
  • A (position 1) →\to D (position 4): +3+3
  • D (position 4) →\to G (position 7): +3+3
    Every letter is shifted forward by +3+3 positions in the English alphabet.

Applying the same +3+3 shift to SWAN:

  • S (position 19) +3=22→+ 3 = 22 \to V
  • W (position 23) +3=26→+ 3 = 26 \to Z
  • A (position 1) +3=4→+ 3 = 4 \to D
  • N (position 14) +3=17→+ 3 = 17 \to Q
    Thus, SWAN is coded as VZDQ.
Final answer

B

Common trap

Shifting the last letter incorrectly, for example adding +2+2 instead of +3+3 to get P instead of Q.

The answer is the one in the official GATE answer key. The solution is this site's own explanation.

Source

Paper
GATE 2015 Computer Science and Information Technology (CS) Session 3
Question
1 of 65, printed as GA Q.1
Section
General Aptitude

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