Question

Consider the following three statements about link state and distance vector routing protocols, for a large network with 500 network nodes and 4000 links.

[S1] The computational overhead in link state protocols is higher than in distance vector protocols.
[S2] A distance vector protocol (with split horizon) avoids persistent routing loops, but not a link state protocol.
[S3] After a topology change, a link state protocol will converge faster than a distance vector protocol.

Which one of the following is correct about S1, S2, and S3 ?

Choose one option
Official answer and solution
Official answer
D
From
Official GATE 2014 answer key

Solution

Compare properties of Link State and Distance Vector routing protocols with respect to computational overhead, convergence time, and loop avoidance.

Evaluate the statements for the large network:

  • [S1]: 'The computational overhead in link state protocols is higher than in distance vector protocols.'
    Link state protocols require each router to maintain full network topology and run Dijkstra's shortest path algorithm (O(Vlog⁡V+E)O(V \log V + E)), which demands significantly more CPU and memory than distance vector's local Bellman-Ford vector exchanges. Thus S1 is TRUE.

  • [S2]: 'A distance vector protocol (with split horizon) avoids persistent routing loops, but not a link state protocol.'
    Split horizon prevents simple two-node loops, but does NOT prevent loops involving 3 or more nodes (count-to-infinity problem still occurs). In contrast, link state protocols maintain a global topology map and compute a shortest path tree from each node, which is inherently loop-free. Thus S2 is FALSE.

  • [S3]: 'After a topology change, a link state protocol will converge faster than a distance vector protocol.'
    Link state floods Link State Advertisements (LSAs) immediately upon detecting a change, allowing fast convergence across the entire network. Distance vector propagates updates hop-by-hop in periodic intervals, which converges much slower. Thus S3 is TRUE.

Therefore, S1 and S3 are true, but S2 is false (Option D).

Final answer

D

Common trap

Believing that split horizon completely eliminates all routing loops in distance vector protocols.

The answer is the one in the official GATE answer key. The solution is this site's own explanation.

Source

Paper
GATE 2014 Computer Science and Information Technology (CS) Session 1
Question
33 of 65, printed as CS Q.23
Section
Computer Science and Information Technology

Report an error in this question

GATE questions are the work of the organising institutes. This site is independent and is not affiliated with them.