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GATE CS 2011 · Algorithms

Question 7

MCQPrinted as CS Q.71 markWrong answer: −1/3Medium (estimate)

Question

A company needs to develop digital signal processing software for one of its newest inventions. The software is expected to have 40000 lines of code. The company needs to determine the effort in person-months needed to develop this software using the basic COCOMO model. The multiplicative factor for this model is given as 2.8 for the software development on embedded systems, while the exponentiation factor is given as 1.20. What is the estimated effort in person-months?

Choose one option
Official answer and solution
Official answer
A
From
Official GATE 2011 answer key

Solution

Apply the basic COCOMO effort estimation formula using the given multiplicative and exponential parameters.

  1. The basic COCOMO effort equation is:
Effort=a×(KLOC)b\text{Effort} = a \times (\text{KLOC})^b
  1. Convert lines of code to thousands of lines of code:
KLOC=400001000=40\text{KLOC} = \frac{40000}{1000} = 40
  1. Substitute the given parameters a=2.8a = 2.8 and b=1.20b = 1.20:
Effort=2.8×(40)1.20\text{Effort} = 2.8 \times (40)^{1.20}
  1. Evaluating (40)1.20=40×400.2≈40×2.091279=83.651(40)^{1.20} = 40 \times 40^{0.2} \approx 40 \times 2.091279 = 83.651:
Effort≈2.8×83.651=234.223≈234.25 person-months\text{Effort} \approx 2.8 \times 83.651 = 234.223 \approx 234.25\text{ person-months}
Final answer

A

The answer is the one in the official GATE answer key. The solution is this site's own explanation.

Source

Paper
GATE 2011 Computer Science and Information Technology (CS)
Question
7 of 65, printed as CS Q.7
Section
Computer Science and Information Technology

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